Leetcode 1450: Number of students doing homework at a given time

In this Leetcode problem, w are given start and end working times for students, and should return how many students work at a given time queryTime.

Problem statement

Solution

For each student i, we know they work at queryTime if and only if:

startTime[i] <= queryTime <= endTime[i]

We test that condition for each student and return the sum. Here is the full code solution:

func busyStudent(startTime []int, endTime []int, queryTime int) int {
    sum := 0
    n := len(startTime)
    for i := 0; i < n; i++ {
        if queryTime >= startTime[i] && queryTime <= endTime[i] {
            sum++
        }
    }
    return sum
}

Happy coding :)

What’s next:

• Checkout the solution for another problem: Minimum score triangulation of polygon
• Contact me: poitevinpm@gmail.com
• Looking to interview for a software engineer position? Contact me :)